(2x^2-5)-(3x^2+4)=

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Solution for (2x^2-5)-(3x^2+4)= equation:


Simplifying
(2x2 + -5) + -1(3x2 + 4) = 0

Reorder the terms:
(-5 + 2x2) + -1(3x2 + 4) = 0

Remove parenthesis around (-5 + 2x2)
-5 + 2x2 + -1(3x2 + 4) = 0

Reorder the terms:
-5 + 2x2 + -1(4 + 3x2) = 0
-5 + 2x2 + (4 * -1 + 3x2 * -1) = 0
-5 + 2x2 + (-4 + -3x2) = 0

Reorder the terms:
-5 + -4 + 2x2 + -3x2 = 0

Combine like terms: -5 + -4 = -9
-9 + 2x2 + -3x2 = 0

Combine like terms: 2x2 + -3x2 = -1x2
-9 + -1x2 = 0

Solving
-9 + -1x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + -1x2 = 0 + 9

Combine like terms: -9 + 9 = 0
0 + -1x2 = 0 + 9
-1x2 = 0 + 9

Combine like terms: 0 + 9 = 9
-1x2 = 9

Divide each side by '-1'.
x2 = -9

Simplifying
x2 = -9

Reorder the terms:
9 + x2 = -9 + 9

Combine like terms: -9 + 9 = 0
9 + x2 = 0

The solution to this equation could not be determined.

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